Ecuacin de Hojstrup

Tal y como est escrita en VB.NET



spec_i = (((7500 / U(i)) / (1 + (2.2 * ((freq * 3000 / U(i)) ^ (5 / 3))))) + ((52.5 * (z(i) / U(i))) / ((1 + 33 * (freq * z(i) / U(i))) ^ (5 / 3)))) * (1 / (6 + 44.4 * ((z(i) / 3000) ^ (2 / 3))))
spec_j = (((7500 / U(j)) / (1 + (2.2 * ((freq * 3000 / U(j)) ^ (5 / 3))))) + ((52.5 * (z(j) / U(j))) / ((1 + 33 * (freq * z(j) / U(j))) ^ (5 / 3)))) * (1 / (6 + 44.4 * ((z(j) / 3000) ^ (2 / 3))))